Part VII · Theory · Chapter 7A

Why hedging works

The Black-Scholes-Merton equation in five steps

Where we are

Part VI followed a dealer through the day: inheriting a customer's Greeks, neutralizing delta, chasing gamma and deciding how often to rebalance. This chapter asks why that recipe works at all and derives the Black-Scholes-Merton equation from the dealer's hedged book in five steps. It then reads the book's profit and loss as a bet on realized against implied volatility.

What you need first
  • Log returns, the square-root-of-time rule and the variance drag μ−12σ2\mu - \tfrac12\sigma^2 (Chapter 1A).
  • The normal distribution and its variance (Chapter 1B), and the random walk (Chapter 3B).
  • Delta, gamma and theta as partial derivatives, the approximation ΔV≈Δ⋅ΔS+12Γ(ΔS)2\Delta V \approx \Delta \cdot \Delta S + \tfrac12\Gamma(\Delta S)^2, and the reference call (Chapter 5C).
  • Implied and realized volatility, and the variance risk premium (Chapter 5E).
  • The delta hedge, and why gamma keeps undoing it (Chapters 6C and 6D).

Up to this point the book has described what the dealer does. This chapter answers a deeper question: why the dealer's delta-hedging strategy is the unique correct strategy, and what mathematical structure its hedging P&L actually has. It is the most technical chapter in the book and also the one that justifies every claim that follows.

If mathematics is not your native language, read slowly and accept the steps one at a time. Each formula is followed by what it says in plain words, while the heaviest algebra sits in boxes you can open or skip. The payoff for that patience is large. By the end of Part VII, one idea organizes every options strategy: every delta-hedged option position is, fundamentally, a bet on realized volatility against implied volatility, and nothing else.

In plain terms

A dealer who holds an option and the right number of shares against it has a book that does not care which way the market moves over the next instant. A book with no risk must earn what cash earns, or else someone could borrow cash, buy the book and keep the difference without risk. That one requirement, no free money, pins down the option's price. What is left of the book's profit and loss is gamma's gain from the size of each move, set against theta's charge for the passing of time.

1 · Five steps from a hedged book to an equation

The derivation runs in five steps, each building on the last and each doing one specific piece of intellectual work:

  1. A model for prices: assume the underlying follows geometric Brownian motion (GBM).
  2. Itô's lemma: derive how the option's value changes when the price moves at random.
  3. The hedged book: build the delta-hedged portfolio and see that it has no random part.
  4. No arbitrage: a portfolio with no risk over the next instant must earn the risk-free rate.
  5. The Black-Scholes-Merton equation: write down what that demands of the option's value, a consistency condition.

After the five steps comes the gamma-theta P&L decomposition that Chapter 5C previewed, which drives everything in the dealer-mechanics framework. The chapter ends by connecting option replication to variance swaps and to the way the VIX is built, the bridge to Part IX.

2 · A model for prices

Black and Scholes (1973) and, independently, Merton (1973) assumed that the underlying's price follows a geometric Brownian motion. That phrase rests on two older ideas: the random walk, and the Brownian motion it becomes when its steps grow very small.

From coin flips to Brownian motion

A random walk (Chapter 3B) is a path built from independent steps. The plainest version flips a fair coin at each step, moving up by hh on heads and down by hh on tails. Each step has mean zero and variance h2h^2. Because the steps are independent, their variances add, so after nn steps the position has mean zero and variance nh2n h^2. Its standard deviation is hnh\sqrt{n}, the square-root-of-time rule of Chapter 1A.

Now let each step take Δt\Delta t years, so that nn steps cover t=n Δtt = n\,\Delta t years. To give the walk a volatility σ\sigma, its variance after one year must be σ2\sigma^2 however finely the year is sliced, which fixes the size of each step:

h=σΔt h = \sigma\sqrt{\Delta t} (7A.1)

With this step, the variance after tt years is nσ2Δt=σ2tn\sigma^2\Delta t = \sigma^2 t, whatever Δt\Delta t is. The step must shrink like the square root of the time it takes, not like the time itself. That one scaling rule is the source of everything unusual in this chapter.

Worked example: Why the step shrinks like a square root

Step 1: the right scaling, the square root. Take σ=0.20\sigma = 0.20 and monthly steps, so that Δt=1/12\Delta t = 1/12 and (7A.1) gives h=0.20×0.289=0.0577h = 0.20 \times 0.289 = 0.0577. Twelve such steps give a standard deviation of 0.0577×12=0.200.0577 \times \sqrt{12} = 0.20. With daily steps, Δt=1/252\Delta t = 1/252 and h=0.0126h = 0.0126, and 252 of them give 0.0126×15.87=0.200.0126 \times 15.87 = 0.20 again.

Step 2: the wrong scaling, in proportion to time. Suppose instead that the step shrank in proportion to its time, h=σ Δth = \sigma\,\Delta t. Monthly steps of 0.0167 give a year's standard deviation of 0.0167×3.46=0.0580.0167 \times 3.46 = 0.058. Daily steps of 0.00079 give only 0.00079×15.87=0.0130.00079 \times 15.87 = 0.013. The finer you slice, the less random the year becomes, until the walk is a straight line.

As Δt\Delta t shrinks toward zero with the right scaling, the coin-flip walk converges to a Brownian motion, written WtW_t. The sum of many small independent steps is close to normal, whatever each step looks like, so the coin flips disappear into a bell curve. A Brownian motion has four defining properties:

  • It starts at zero: W0=0W_0 = 0.
  • Its change over any interval of length Δt\Delta t is normally distributed, with mean zero and variance Δt\Delta t.
  • Its changes over intervals that do not overlap are independent of each other.
  • Its path is continuous, with no jumps.

The path is continuous but so jagged that it has no slope at any point: zoom in on any stretch and it looks as rough as the whole. The notation dWdW means its change over a very short time dtdt. That change is normal, with mean zero and variance dtdt, so its typical size is dt\sqrt{dt}. For short times dt\sqrt{dt} is far larger than dtdt: one trading day is dt=1/252=0.0040dt = 1/252 = 0.0040 of a year, but dt=0.063\sqrt{dt} = 0.063, almost 16 times larger.

Adding a steady trend gives Brownian motion with drift, Xt=a t+b WtX_t = a\,t + b\,W_t: a line of slope aa with noise of volatility bb wrapped around it. Chapter 1D used it for the logarithm of an account's wealth, which drifts at the growth rate GG with volatility σ\sigma.

Geometric Brownian motion

Geometric Brownian motion applies the noise to the price in proportion to the price:

dS=μS dt+σS dW dS = \mu S\,dt + \sigma S\,dW (7A.2)

In words: in a small instant of time dtdt, the price SS changes by a deterministic amount, μS dt\mu S\,dt, called the drift, and a random amount, σS dW\sigma S\,dW, called the diffusion. Here μ\mu is the expected return per year and σ\sigma the volatility. By construction, dWdW is normally distributed with mean zero and variance dtdt.

Multiplying the noise by σS\sigma S scales it by the current price and the volatility. That makes volatility a percentage per unit of time rather than a number of dollars per unit of time. It matches what you see in markets, where volatility scales with the price level: a $1,000 stock has bigger dollar moves than a $10 stock at the same volatility. Dividing both sides by SS gives the form Chapter 1A used, dS/S=μ dt+σ dWdS/S = \mu\,dt + \sigma\,dW. The simple return over the instant is a drift plus normal noise.

This is the central modeling assumption of the entire Black-Scholes framework. Prices wiggle in proportion to themselves, which makes log returns normally distributed, or Gaussian, in continuous time. The model is wrong: real returns have fat tails, as Chapter 1B established. But it is wrong in ways that can be corrected at the margins without rebuilding the whole framework. For establishing why dealers hedge the way they do, geometric Brownian motion is fine.

One subtlety needs care: the parameter μ\mu is the instantaneous expected return in simple-return space, not in log-return space. The expected log return is μ−12σ2\mu - \tfrac12\sigma^2, the variance drag of Chapter 1A, which Step 2 derives. The two parameters live in different return conventions, both valid as long as you know which one you are using.

Worked example: One day of drift against one day of noise

Step 1: the drift over one trading day. With S=100S = 100, μ=0.08\mu = 0.08, σ=0.20\sigma = 0.20 and dt=1/252dt = 1/252, the drift is μS dt=8/252=0.032\mu S\,dt = 8/252 = 0.032, about 3 cents.

Step 2: the noise over the same day. The random part has a standard deviation of σSdt=20×0.063=1.26\sigma S\sqrt{dt} = 20 \times 0.063 = 1.26, about $1.26, so on a typical day the noise is 40 times the drift.

Step 3: square both. The drift squared is only 0.0322=0.00100.032^2 = 0.0010, while the noise squared averages its variance, 1.262=1.591.26^2 = 1.59, about 1,600 times larger. Step 2 of the derivation turns on this gap.

3 · Itô's lemma

The option's value depends on the price and on time, V(S,t)V(S, t), so it moves whenever SS moves. Ordinary calculus has a rule for this, the chain rule, which would give dV=(∂V/∂S) dSdV = (\partial V/\partial S)\,dS for the price's part. That is wrong here, because SS is random. The correct rule is Itô's lemma, the chain rule for Brownian motion. It rests on one surprising fact: a squared move does not vanish.

Why the square of a move does not vanish

For a smooth path, the change over a short time dtdt is proportional to dtdt, so its square is proportional to dt2dt^2. Over a year cut into nn steps, those squares add up to n×(1/n)2=1/nn \times (1/n)^2 = 1/n, which vanishes as the steps shrink. That is why ordinary calculus drops every squared change.

A Brownian motion behaves differently, because each squared step (ΔW)2(\Delta W)^2 has mean Δt\Delta t, the variance of the step. The squared steps over a year add up to a total whose mean is 1, a full year, however finely you slice. Its spread shrinks as the slicing gets finer, because the squared steps are independent: for normal steps, the total's standard deviation is 2/n\sqrt{2/n}.

Worked example: Adding up squared steps over one year

The table cuts one year into monthly, daily and five-minute steps (78 five-minute bars in a trading day, 252 trading days).

Steps in the yearSum of (ΔW)2(\Delta W)^2: meanIts standard deviationSum of (Δt)2(\Delta t)^2
1210.410.083
25210.0890.0040
19,65610.0100.00005

Step 1: read the last column, the squared time steps. They add up to 1/n1/n, which vanishes as the steps multiply.

Step 2: read the middle columns, the squared Brownian steps. They add up to the elapsed time, 1 year, with a spread that falls from 41% to 1%, so that in the limit the sum is the elapsed time.

The running sum of a path's squared changes is its quadratic variation, which for Brownian motion grows exactly like time. That result is usually written as three rules for products of small changes:

ProductBecomesWhy
dt×dtdt \times dt0summed over a year it is 1/n1/n, which vanishes
dt×dWdt \times dW0each is of size dt3/2dt^{3/2}, which also vanishes when summed
dW×dWdW \times dWdtdtsummed, it is the elapsed time

Applied to (7A.2), the rules keep only the noise's contribution to the squared move:

(dS)2=σ2S2 dt (dS)^2 = \sigma^2 S^2\,dt (7A.3)

The drift's square and the cross term vanish, as the worked example suggested. Over one day the drift squared was 1,600 times smaller than the noise squared, a gap that widens as the interval shrinks.

Familiar ground

The rule that (dW)2=dt(dW)^2 = dt is the law of large numbers you rely on in every trial. One patient's response to a drug is unpredictable, while the response rate across 1,000 patients is pinned down tightly. Each squared step of a Brownian path is likewise a noisy measurement of the time it took, with a standard deviation about 1.4 times its mean. Add up thousands of them and the noise averages away, leaving the elapsed time. The relative spread falls as 2/n\sqrt{2/n}, just as a sample mean's standard error falls as 1/n1/\sqrt{n}.

The chain rule with one more term

Chapter 5C approximated a change in value by delta times the move plus half of gamma times the move squared. Written for a function of both price and time, that second-order Taylor expansion is

dV≈∂V∂tdt+∂V∂SdS+12∂2V∂S2(dS)2 \begin{aligned} dV \approx{}& \frac{\partial V}{\partial t}dt + \frac{\partial V}{\partial S}dS \\ &+ \tfrac12\frac{\partial^2 V}{\partial S^2}(dS)^2 \end{aligned} (7A.4)

plus terms in dt2dt^2, dt dSdt\,dS and higher powers, all of which vanish by the rules above. In ordinary calculus the (dS)2(dS)^2 term vanishes too, but here, by (7A.3), it is σ2S2 dt\sigma^2S^2\,dt, of the same order as dtdt. Substituting it gives Itô's lemma, the chain rule for a random price:

dV=∂V∂tdt+∂V∂SdS+12∂2V∂S2σ2S2 dt \begin{aligned} dV ={}& \frac{\partial V}{\partial t}dt + \frac{\partial V}{\partial S}dS \\ &+ \tfrac12\frac{\partial^2 V}{\partial S^2}\sigma^2 S^2\,dt \end{aligned} (7A.5)

The extra term is there because (dS)2(dS)^2 is not zero. For ordinary smooth functions, (dx)2(dx)^2 is of order dt2dt^2, which you drop in the limit. For Brownian motion, the variance of dSdS over the interval dtdt is σ2S2 dt\sigma^2S^2\,dt, of the same order as dtdt itself, which you must keep. The term 12(∂2V/∂S2) σ2S2 dt\tfrac12(\partial^2V/\partial S^2)\,\sigma^2S^2\,dt is gamma showing up explicitly. It is the quadratic variation contribution that makes options different from linear instruments.

This is the central technical insight of stochastic calculus. The second derivative matters when the underlying is random, and not when it is deterministic. Every "interesting" property of options derives from this single mathematical fact.

In the notation of Chapter 5C, where ∂V/∂S=Δ\partial V/\partial S = \Delta, ∂2V/∂S2=Γ\partial^2V/\partial S^2 = \Gamma and ∂V/∂t=Θ\partial V/\partial t = \Theta, Itô's lemma becomes

dV=Θ dt+Δ dS+12Γσ2S2 dt dV = \Theta\,dt + \Delta\,dS + \tfrac12\Gamma\sigma^2S^2\,dt (7A.6)

Read it this way: over a small interval, the option's value changes by a time-decay piece, Θ dt\Theta\,dt, a directional piece, Δ dS\Delta\,dS, which moves with the underlying, and a curvature piece, 12Γσ2S2 dt\tfrac12\Gamma\sigma^2S^2\,dt. The curvature piece is always positive for long-option positions and reflects the convexity benefit.

Worked example: Itô's lemma on the logarithm of the price

Step 1: the derivatives of the logarithm. Take V=ln⁡SV = \ln S, which does not depend on time, so its only derivatives are the first, 1/S1/S, and the second, −1/S2-1/S^2.

Step 2: apply (7A.5). The curvature term is 12×(−1/S2)×σ2S2 dt=−12σ2 dt\tfrac12 \times (-1/S^2) \times \sigma^2S^2\,dt = -\tfrac12\sigma^2\,dt, so dln⁡S=dS/S−12σ2 dtd\ln S = dS/S - \tfrac12\sigma^2\,dt. Substituting dS/S=μ dt+σ dWdS/S = \mu\,dt + \sigma\,dW from (7A.2) gives

dln⁡S=(μ−12σ2) dt+σ dW d\ln S = (\mu - \tfrac12\sigma^2)\,dt + \sigma\,dW (7A.7)

Step 3: read it. The log price is a Brownian motion with drift μ−12σ2\mu - \tfrac12\sigma^2: the variance drag of Chapter 1A, now exact. With μ=8%\mu = 8\% and σ=20%\sigma = 20\%, the log price grows at 0.08−0.02=6%0.08 - 0.02 = 6\% a year. The ordinary chain rule, which drops the curvature term, would have said 8%.

4 · The hedged book

Now build the dealer's book. Suppose the dealer has bought an option from a customer and hedges it by selling Δ\Delta shares of the underlying, the delta hedging of Chapter 6C. The book is worth

Π=V−ΔS \Pi = V - \Delta S (7A.8)

where Δ=∂V/∂S\Delta = \partial V/\partial S is set at the start of the instant and held fixed through it. Over the instant the short shares lose Δ dS\Delta\,dS, so the book changes by dΠ=dV−Δ dSd\Pi = dV - \Delta\,dS. When (7A.6) is substituted for dVdV, its Δ dS\Delta\,dS meets the −Δ dS-\Delta\,dS of the shares and cancels it:

dΠ=(Θ+12Γσ2S2) dt d\Pi = (\Theta + \tfrac12\Gamma\sigma^2S^2)\,dt (7A.9)

Look at what just happened: the dSdS terms canceled. The book's change has no random component, so over the instant it is risk-free. That is what delta hedging accomplishes: it removes the dWdW term and leaves only the deterministic dtdt terms.

This is the mathematical statement of what Chapter 6C said informally: a delta-hedged book is, at the instant of the hedge, directionless. The dWdW noise from the underlying has been hedged away. The remaining motion of the book is entirely deterministic, driven by theta and gamma alone, at first order.

Two remarks keep this honest. The first is that "at the instant" matters: delta changes as soon as SS moves, so the hedge must be reset continually, which is gamma's chase in Chapter 6D. The second is that a dealer who sold the option holds −Π-\Pi, long Δ\Delta shares against a short option. Every sign flips, while the argument that follows is unchanged.

5 · No free money

A book that is risk-free over the next instant must earn the risk-free rate rr, otherwise there is free money. This is the no-arbitrage condition, the most consequential single principle in derivatives pricing. If the hedged book earned more than rr, a trader could borrow at rr, buy the book and keep the difference with no risk, an arbitrage. If the book earned less, the trader would short it and lend the proceeds at rr. Either trade pushes prices until the gap closes, so

dΠ=r Π dt d\Pi = r\,\Pi\,dt (7A.10)

The book earns the risk-free rate on its current value. Combining this with (7A.9), and writing Π=V−ΔS\Pi = V - \Delta S:

(Θ+12Γσ2S2) dt=r(V−ΔS) dt (\Theta + \tfrac12\Gamma\sigma^2S^2)\,dt = r(V - \Delta S)\,dt (7A.11)

Cancel dtdt from both sides and rearrange:

Θ+12Γσ2S2=rV−rΔS \Theta + \tfrac12\Gamma\sigma^2S^2 = rV - r\Delta S (7A.12)

6 · The Black-Scholes-Merton equation

Write the Greeks back out as derivatives and move rΔSr\Delta S to the left:

∂V∂t+rS∂V∂S+12σ2S2∂2V∂S2=rV \begin{aligned} &\frac{\partial V}{\partial t} + rS\frac{\partial V}{\partial S} \\ &\quad + \tfrac12\sigma^2S^2\frac{\partial^2 V}{\partial S^2} = rV \end{aligned} (7A.13)

This is the celebrated Black-Scholes-Merton partial differential equation (PDE). A partial differential equation is a relation among a function's partial derivatives. Its solution is not a number but a whole function, here the option's value at every price and time, fixed once you say what it must equal at expiry. Robert Merton received the 1997 Nobel Memorial Prize in Economics for this work, jointly with Myron Scholes. Fischer Black, who would have shared the prize, had died in 1995.

Worked example: The reference call satisfies the equation

Chapter 5C's reference call has S=K=100S = K = 100, 30 days to expiry, σ=0.25\sigma = 0.25, r=0.04r = 0.04 and no dividend. Its value is 3.0211, its delta 0.53256, its gamma 0.055476 and its theta −19.3457 a year.

Step 1: the time term. The first term of (7A.13) is theta itself, −19.3457-19.3457.

Step 2: the delta term. The second term, the interest on the shares the delta represents, is rSΔ=0.04×100×0.53256=2.1302rS\Delta = 0.04 \times 100 \times 0.53256 = 2.1302.

Step 3: the gamma term. The third term, gamma's curvature, is 12σ2S2Γ=0.5×0.0625×10,000×0.055476=17.3363\tfrac12\sigma^2S^2\Gamma = 0.5 \times 0.0625 \times 10{,}000 \times 0.055476 = 17.3363.

Step 4: compare the sides. The left side sums to −19.3457+2.1302+17.3363=0.1208-19.3457 + 2.1302 + 17.3363 = 0.1208, exactly the right side, rV=0.04×3.0211=0.1208rV = 0.04 \times 3.0211 = 0.1208, to four decimals.

With a dividend yield qq, the short shares in the book pay out q ΔS dtq\,\Delta S\,dt over each instant. Carrying that cost through Steps 3 and 4 turns the term rS ∂V/∂SrS\,\partial V/\partial S into (r−q)S ∂V/∂S(r - q)S\,\partial V/\partial S. That is the version whose solution carries the factor e−qTe^{-qT} of Chapter 5C's formula.

A consistency condition, not a formula

The Black-Scholes-Merton PDE is not a pricing formula but a consistency condition: any option price function V(S,t)V(S, t) that does not satisfy it creates an arbitrage. Solve it with the condition that at expiry, with no time left, a call is worth max⁡(S−K,0)\max(S - K, 0). The solution is the Black-Scholes call formula of Chapter 5C, with d1d_1 and d2d_2 as defined there:

C=Se−qTN(d1)−Ke−rTN(d2) C = S e^{-qT}N(d_1) - K e^{-rT}N(d_2) (7A.14)

More profoundly, the PDE encodes the recipe by which a dealer can replicate the option using only the underlying and cash. The dealer is not "pricing the option" in some metaphysical sense but manufacturing it through dynamic hedging. The shares and cash, adjusted as the price moves, form a replicating portfolio that ends with exactly the option's payoff.

This is the deepest insight in the entire framework. An option's payoff looks as if it needs unusual cleverness to construct, because it is asymmetric and convex. In fact it can be built from a simple time-varying position in the underlying plus cash. The cost of building it is exactly the Black-Scholes price, no more and no less, under the model's assumptions. Any deviation from that price creates an arbitrage.

The practical implication is that when you buy an option, you are buying the right to a payoff that the dealer constructs for you through their hedging. The premium you pay is the cost of the construction kit, plus the dealer's margin, plus compensation for residual risks the model does not capture: jump risk, transaction costs and fat tails. The variance risk premium of Chapter 5E is the cumulative spread between what dealers charge and what the model says is fair. It is the structural compensation dealers require to be in this business.

Where the expected return went

Look again at (7A.13): the expected return μ\mu appears nowhere in it. It entered through the price model, (7A.2), and reached Itô's lemma through dSdS. It disappeared in Step 3, when the hedge canceled the dSdS terms, the only route by which the drift could reach the book. So the option's price does not depend on how fast anyone expects the underlying to grow.

That settles the question Chapter 4B left open: which probabilities turn an expected payoff into a price. Because μ\mu does not matter, you may price as if the underlying grew at the risk-free rate, then discount the expected payoff at that rate. Probabilities chosen that way are the risk-neutral probabilities of Chapter 5C.

Worked example: One step of replication

Step 1: the setup. Take Chapter 4B's toy, with r=0r = 0 to keep the arithmetic clean: an underlying at 100 ends at 110 or 90, where a call struck at 100 pays 10 or 0.

Step 2: build the replica. Hold aa shares and bb dollars of cash, and require the replica to pay what the call pays in both outcomes: 110a+b=10110a + b = 10 and 90a+b=090a + b = 0. Subtracting gives 20a=1020a = 10, so a=0.5a = 0.5 and b=−45b = -45, a loan of $45. The share count aa is the call's delta over the step.

Step 3: its cost. The replica costs 0.5×100−45=50.5 \times 100 - 45 = 5 today, so the call must also cost 5, or buying one and selling the other is an arbitrage.

Step 4: the probabilities do not matter. With a 50% chance of the rise, the expected payoff is 5, the price. With a 70% chance, the expected payoff is 7. The replica still costs 5, so the price is still 5. The probability that makes the expected payoff equal the price is the one under which the underlying's expected value is today's price, which here is 50%: the risk-neutral probability.

7 · The hedging P&L: gamma against theta

Now the PDE gives the most important formula in this book. Suppose the dealer delta-hedges continuously while the realized volatility σR\sigma_R differs from the volatility used to price the option, the implied volatility at entry σI\sigma_I. Over each instant, the book's gain above what the same money would earn as cash is approximately

dΠ−rΠ dt≈12ΓS2×[(dSS)2−σI2 dt] \begin{aligned} d\Pi - r\Pi\,dt \approx{}& \tfrac12\Gamma S^2 \\ &\times \Big[\Big(\frac{dS}{S}\Big)^2 - \sigma_I^2\,dt\Big] \end{aligned} (7A.15)

where Γ\Gamma is computed at the implied volatility.

Where the hedging P&L comes from

Step 1: expand using the actual move. The dealer values and hedges the option at σI\sigma_I, so Θ\Theta, Δ\Delta and Γ\Gamma are the Black-Scholes values at σI\sigma_I. Over the instant, the Taylor expansion gives dV≈Θ dt+Δ dS+12Γ(dS)2dV \approx \Theta\,dt + \Delta\,dS + \tfrac12\Gamma(dS)^2. Here (dS)2(dS)^2 is the square of the move that actually happened, not its model average.

Step 2: add the hedge and the financing. The short shares cancel Δ dS\Delta\,dS, as in Step 3. Subtracting what the book would have earned as cash, r(V−ΔS) dtr(V - \Delta S)\,dt, leaves

dΠ−rΠ dt≈12Γ(dS)2+(Θ−rV+rΔS) dt \begin{aligned} d\Pi - r\Pi\,dt \approx{}& \tfrac12\Gamma(dS)^2 \\ &+ (\Theta - rV + r\Delta S)\,dt \end{aligned} (7A.16)

Step 3: use the PDE at the implied volatility. The option's price satisfies (7A.12) with σI\sigma_I in place of σ\sigma, which, rearranged, says Θ−rV+rΔS=−12ΓσI2S2\Theta - rV + r\Delta S = -\tfrac12\Gamma\sigma_I^2S^2.

Step 4: substitute and factor. The second term of Step 2 becomes −12ΓσI2S2 dt-\tfrac12\Gamma\sigma_I^2S^2\,dt, so that factoring out 12ΓS2\tfrac12\Gamma S^2 gives (7A.15). The only change from Step 3 of the derivation is that the squared move is now the realized one, not σI2S2 dt\sigma_I^2S^2\,dt.

Read (7A.15) this way: over each interval, the delta-hedged dealer earns gamma times the difference between the realized squared return and the implied variance. This is the entire economic content of a delta-hedged option position. If the squared returns average the implied variance, the bracket averages zero and the book earns nothing beyond cash. If they do not, the book earns or pays the difference, scaled by 12ΓS2\tfrac12\Gamma S^2, with these signs:

  • If you are long the option (long gamma) and realized volatility exceeds implied, you make money. Every wiggle in spot lets you scalp gamma, buying low and selling high in your hedge, at a rate that in aggregate exceeds the theta you are paying.
  • If you are long the option and realized falls short of implied, you lose, because you bought too much volatility.
  • If you are short the option (short gamma, the dealer's typical position), the signs flip. You earn the implied volatility, as the theta you collect, and pay the realized volatility, as the rebalancing losses.

A short-gamma dealer wants quiet markets, while a long-gamma dealer wants moves.

Worked example: One day, then sixty

Take the figure below at its starting settings: a long at-the-money option, strike 100 with spot at 100, 60 trading days to expiry, implied volatility 20% and a 4% rate. Its gamma is 0.0404, so 12ΓS2=202\tfrac12\Gamma S^2 = 202 per share, with time counted in trading days, dt=1/252dt = 1/252.

Step 1: the breakeven move. The bracket in (7A.15) is zero when ∣dS/S∣=σIdt=0.20/15.87=1.26%|dS/S| = \sigma_I\sqrt{dt} = 0.20/15.87 = 1.26\%. Days with larger moves pay the hedged long option, while days with smaller moves cost it.

Step 2: a day at 30% realized volatility. A typical day at 30% is a move of 0.30/15.87=1.89%0.30/15.87 = 1.89\%, which makes the bracket 0.000357−0.000159=0.0001980.000357 - 0.000159 = 0.000198. The day earns 202×0.000198=0.040202 \times 0.000198 = 0.040 a share, or $4.01 a contract of 100.

Step 3: quieter days. A 0.5% move gives 202×(0.000025−0.000159)=−0.027202 \times (0.000025 - 0.000159) = -0.027 a share, a loss of $2.70 a contract. A day with no move at all costs $3.21, the full implied variance of one day.

Step 4: sixty days. If 12ΓS2\tfrac12\Gamma S^2 stayed at 202, sixty typical days at 30% would earn about 60×$4.01=$24160 \times \$4.01 = \$241. It does not stay there, because spot wanders away from the strike, where gamma is smaller. The figure's average over its 99 seeds is about $180, with every one of them ending positive.

Key idea

Under the standard delta-hedged framework, an option position is, at first order, a bet on realized against implied volatility. It is the dominant P&L driver in the absence of large vega or skew dynamics.

This is the punchline of the gamma-theta decomposition. Three choices set up the bet: strike selection affects the size of gamma, expiration selection affects its speed, and the implied volatility at entry sets the implied side. To first order, the resulting P&L is a function of whether realized exceeded implied.

The figure runs (7A.15) one day at a time. Its top panel draws a simulated spot path whose volatility is the realized-vol setting. Its bottom panel accumulates the hedged P&L of one contract of an at-the-money option, strike 100 with 60 trading days to expiry, with gamma computed at the implied vol.

Two sliders set the implied and the realized vol, from 5% to 60%, starting at 20% and 30%. A third picks the path seed, from 1 to 99, starting at 7. A switch flips the position between long and short gamma. Three readouts give the volatility the path actually realized, the terminal P&L and the sign that realized against implied predicts. Step through a few seeds, then set realized equal to implied, then below it, and flip to short gamma.

20%
30%
#7
realized vol = 30.1%
terminal P&L (long Γ) = +$123
predicted sign = positive
A delta-hedged option is a bet on realized against implied. One at-the-money option (strike 100, 60 trading days to expiry) on a simulated spot path whose volatility is the realized-vol setting, top; below, its hedged P&L for one contract, the running sum of ½Γ·S²·[(dS/S)² − σ²·dt] with σ the implied vol, taken one day at a time. Move the path seed for a new path, or flip the position to short gamma. With realized well above implied the long-gamma P&L climbs; with it well below, the P&L bleeds.

At the starting settings, seed 7's path realizes 30.1% and the long-gamma book ends about $123 up, as predicted. At 30% realized, every seed ends positive, but by amounts from about $35 to over $600: the sign is reliable, while the size depends on the path. With realized set equal to implied, the final P&L scatters around zero, from about −$160 to +$170. At 10% realized every seed loses. The predicted sign compares the path's realized volatility, not the slider's, with implied. Flipping to short gamma turns each curve upside down, because the short book earns what the long book pays.

The honest caveats

The "and nothing else" framing skips several real-world second-order effects that matter in practice:

  • Vega risk on IV moves: a delta-hedged position is not vega-neutral. If implied volatility changes between entry and exit, that mark-to-market vega P&L is a separate component on top of the gamma-against-realized term. For long-dated options with large vega, it can dominate.
  • Discrete hedging: the decomposition assumes continuous rebalancing, while real hedging happens in steps. The path of spot between rebalances adds variance around the theoretical gamma-scalping P&L. Two traders running the same position with different hedge frequencies realize different P&L from the same gap between realized and implied.
  • Skew and surface dynamics: options that sit on a steep part of the volatility surface accrue P&L from vanna and volga as spot and volatility move together. Those terms are not captured by the simple Γ×(σR2−σI2)\Gamma \times (\sigma_R^2 - \sigma_I^2) decomposition, and Chapter 7B works them through.
  • Transaction costs: hedging is not free, so the gamma-scalping P&L is gross. Net P&L can be meaningfully smaller, especially in less liquid underlyings or on short-DTE options, where rebalancing is frequent.

For most retail-scale, short-to-medium-DTE, large-cap delta-hedged positions, the first-order framing of realized against implied captures the bulk of P&L variability. For longer-dated positions, exotic surface trades or low-liquidity underlyings, the second-order terms matter and should be modeled explicitly.

Hedging in steps, and paying for each step

The second and fourth caveats pull against each other, as Chapter 6E showed. Hedging more often tames the path's noise but pays the spread more often. The next figure puts both into one book. It holds long at-the-money calls on a $600 underlying and delta-hedges them along one simulated path of five-minute bars, 78 to a trading day. The path's volatility equals the implied volatility, so hedging continuously earns nothing on average before costs.

Four schedules hedge the same path: on every bar (the row labeled continuous), five times a day, at each daily close and every three days. On each bar, a schedule's P&L adds up three things. The first is the gamma-theta term of (7A.15). The second is the delta that the stale hedge leaves open, the calls' delta at the start of the bar less the hedge held, times the bar's move. The third is the cost of any rebalance, including the first hedge: the shares traded, times the price, times the transaction cost.

Hedging on every bar leaves no delta open, so that schedule's curve is the pure gamma-theta P&L less its costs. Sliders set the implied vol (5% to 80%, starting at 20%), the days to expiry, labeled DTE (5 to 90, starting at 30), and the number of contracts (1 to 500, starting at 100). Two more set the transaction cost (0 to 20 basis points, starting at 2) and the seed (1 to 500, starting at 7). Below the chart, a table gives each schedule's final P&L. Set the cost to zero and step through seeds, then raise the cost.

20%
30d
100
2.0
7
Hedge frequencyFinal P&L
Continuous (theoretical)−$21,529
Intraday (5 hedges/day)−$15,167
Daily close+$11,548
Every 3 days+$4,471
One path, four hedging schedules. Long at-the-money calls on a $600 underlying, delta-hedged along one simulated path of five-minute bars whose volatility equals the implied vol, so hedging continuously earns nothing on average before costs. The curves differ only in how often the hedge is reset, and every reset pays the transaction cost on the shares traded. Across seeds, the less often the hedge is reset the wider the spread of final P&L, while the cost slider hits the most frequent hedger hardest.

At the starting settings, the 100 calls carry about 5,340 shares of delta. Hedging on every bar rebalances 2,339 times and ends about $21,500 down, of which about $19,400 is transaction cost. Five hedges a day end about $15,200 down, the daily close about $11,500 up and every three days about $4,500 up. All four share the same gamma-theta term, a loss of about $2,100 on this path, so everything else in each result is open delta and cost.

One seed proves little, so look across all 500 of the figure's seeds. At zero cost the four schedules each average close to zero, while the spread of final P&L widens as hedging gets rarer. Its standard deviation is about $3,100 hedging every bar, $9,600 at five a day, $20,600 daily and $35,600 every three days. At 2 basis points the average cost runs the other way: about $19,000, $5,400, $2,700 and $1,800.

Both patterns follow square-root rules in the hedging interval δt\delta t. Over one interval the move, and with it the open delta, grows like δt\sqrt{\delta t}, which makes the error the interval adds grow like δt\delta t. Summed over T/δtT/\delta t independent intervals, the total error grows like δt\sqrt{\delta t}. Hedging five times less often gives about 5=2.2\sqrt5 = 2.2 times the spread, as from $9,600 to $20,600. The shares traded at each rebalance also grow like δt\sqrt{\delta t}. The number of rebalances, though, falls like 1/δt1/\delta t, so the total cost grows like 1/δt1/\sqrt{\delta t} as the interval shrinks. Hedging about 15 times as often, 2,339 rebalances against 155, should cost about 15=3.9\sqrt{15} = 3.9 times as much, and the figure gives 3.5.

No schedule wins on both counts: the spread falls as the interval shrinks while the cost rises. That is the trade-off of Chapter 6E, which finds where the net result is best for an SPX book.

8 · Why the dealer feedback loop is built into the math

This is also the punchline for why aggregate dealer positioning moves the market. Suppose dealers are collectively short gamma. By (7A.15) they are mechanically losing money to volatility. The more volatility there is, the more they lose. To minimize losses they hedge aggressively, which means buying as the market rises and selling as it falls. That hedging creates volatility, which makes them lose more, which makes them hedge more.

The feedback loop is mathematically built into the gamma-theta decomposition just derived. It is not a story or a metaphor: it falls out of the PDE. Chapter 8D formalizes it into the effective-volatility equation, which quantifies how dealer feedback amplifies or dampens the underlying's volatility depending on the sign of aggregate dealer gamma.

9 · The variance swap connection

Add up (7A.15) over the life of the option. Each instant's gain is weighted by 12ΓS2\tfrac12\Gamma S^2, which changes as spot and time move. Now suppose you held a position whose gamma falls like 1/S21/S^2 as spot rises, so that ΓS2\Gamma S^2 stays at a constant, gg. The weight then comes out of the sum. Write PP for the book's total gain above cash over a life of TT years:

P≈g2[∑(dSS)2−σI2T]=g2 T (σR2−σI2) \begin{aligned} P &\approx \tfrac{g}{2}\Big[\sum\Big(\frac{dS}{S}\Big)^2 - \sigma_I^2 T\Big] \\ &= \tfrac{g}{2}\,T\,(\sigma_R^2 - \sigma_I^2) \end{aligned} (7A.17)

Here σR2=1T∑(dS/S)2\sigma_R^2 = \tfrac{1}{T}\sum (dS/S)^2 is the realized variance, annualized. A payoff proportional to realized variance less a fixed number is exactly a variance swap (Chapter 4B). So integrating the hedging P&L over the life of the option and weighting by 1/S21/S^2 gives, almost exactly, the payoff of a variance swap. This is not coincidence but the foundation of model-free variance replication, and the reason the VIX (Chapter 9A) is constructed as a weighted strip of options with 1/K21/K^2 weights.

Demeterfi, Derman, Kamal and Zou's 1999 Goldman Sachs paper, "More Than You Ever Wanted to Know About Volatility Swaps", showed how. A portfolio of options weighted by ΔK/K2\Delta K/K^2 across all strikes, where ΔK\Delta K is the spacing between strikes, replicates the payoff of a variance swap when it is dynamically delta-hedged. The intuition is that weighting by 1/K21/K^2 creates a "gamma flat" portfolio. Its ΓS2\Gamma S^2, which turns a squared return into dollars and is 100 times the per-share dollar gamma of Chapter 6D, is the same wherever spot is. That is exactly the property required to replicate realized variance.

Worked example: A strip with flat dollar gamma

Take options 30 days from expiry at 20% implied volatility and a zero rate, one at every strike from 40 to 300, $1 apart.

Step 1: a single strike at 100. An option struck at 100 has ΓS2\Gamma S^2 of 695 with spot at 100, but only 122 at spot 90 and 0.32 at spot 80. Its sensitivity to squared returns lives near its strike.

Step 2: equal weights at every strike. One option at every strike gives ΓS2\Gamma S^2 of 6,421 at spot 80, 10,033 at 100 and 14,447 at 120. The sensitivity is spread out now, but it grows with spot.

Step 3: weights of 1/K². Holding 1/K21/K^2 of each option gives ΓS2=1.000\Gamma S^2 = 1.000 at spot 80, at 100 and at 120. Every squared return then counts the same wherever spot has wandered, which is what a variance swap pays for. The flatness is no accident of the numbers. Apart from a straight line, the strip pays minus the logarithm of the final price: a short position in the log contract of Chapter 9A. Minus the logarithm has a gamma of exactly 1/S21/S^2, so ΓS2=1\Gamma S^2 = 1 at every spot.

This is the mathematical thread connecting dealer hedging to the VIX. The VIX is, fundamentally, the cost of replicating variance through delta-hedged options. Every option you trade contributes some amount of replicated variance to the dealer's book. Aggregate dealer gamma is, essentially, the aggregate variance-replication exposure of the entire options ecosystem. Chapter 9A returns to this connection in detail.

In practice
  • An unhedged option is not this bet: a short put you hold without a hedge makes or loses money mostly on direction, through delta. The formula (7A.15) describes only the part of its P&L that a hedge would leave.
  • Know the breakeven move before you trade: it is σI/252\sigma_I/\sqrt{252} a day, 1.26% at 20% implied volatility. A seller of hedged options profits when the squared daily moves average less than its square, and a buyer when they average more.
  • Count the rebalancing costs: a retail account that hedges a short straddle with MES futures (Chapter 2A) pays the spread at every adjustment. Hedging less often saves costs but widens the spread of outcomes, as the friction figure showed.
  • Know what a bought option costs you: its premium pays for the dealer's construction, their margin and the residual risks they carry. The variance risk premium (Chapter 10C) is what that costs a buyer on average.
When it fails

The derivation assumes geometric Brownian motion with one constant volatility, continuous hedging at no cost, and a price that never jumps. When the price gaps, a hedge set before the gap is wrong after it. No rebalancing can follow a move that happens all at once. The dealer then carries the jump risk that the premium was meant to cover. Implied volatility also moves, which is the vega caveat. The surface moves with spot too, which Chapter 7B takes up. Finally, the no-arbitrage step needs someone able to borrow, lend and trade at the model's prices. When capital is scarce, the limits to arbitrage of Chapter 1G can hold prices away from the model's for some time.

Decision rule
  • Treat any option you hedge as a volatility trade: take it only when your forecast of realized volatility over its life differs from the implied volatility by more than your hedging costs. Go long gamma if you expect more realized volatility, short if less.
  • Size a short-gamma book for the large days, not the average day: by (7A.15), a day at twice the breakeven move costs three days of the implied variance the book collects. A day at three times the breakeven costs eight.
  • Choose a hedging interval deliberately: hedging less often widens the spread of outcomes roughly with the square root of the interval. Hedging more often raises costs roughly with one over that square root (Chapter 6E).
Common mistake: "delta-neutral means no risk"

A delta-hedged book has no risk from direction only for an instant. Over a day its P&L is (7A.15), which can be large. A short-gamma book loses eight days' worth of collected implied variance on a single day that moves three times the breakeven. Delta-neutral means the bet has changed from direction to volatility, not that the bet has gone.

Common mistake: reading the PDE as a forecast

The Black-Scholes-Merton equation says nothing about where the price goes, because the expected return has dropped out of it. Risk-neutral probabilities are pricing weights, not forecasts. The N(d2)N(d_2) of Chapter 5C is the chance of a call finishing in the money in a world where the underlying grows at the risk-free rate, not in the real one.

What to carry forward
  • A Brownian motion's change over a time dtdt is normal with variance dtdt, so its squared changes add up to the elapsed time. That is the rule (dW)2=dt(dW)^2 = dt, while (dt)2(dt)^2 vanishes.
  • Itô's lemma is the chain rule plus one term, 12Γσ2S2 dt\tfrac12\Gamma\sigma^2S^2\,dt: gamma earning from the size of moves.
  • A hedge of Δ\Delta shares cancels the random part of the book. No arbitrage then makes the book earn the risk-free rate. Together they give the Black-Scholes-Merton equation, a consistency condition whose solution is the Black-Scholes formula and in which μ\mu does not appear.
  • A continuously hedged book earns 12ΓS2[(dS/S)2−σI2 dt]\tfrac12\Gamma S^2[(dS/S)^2 - \sigma_I^2\,dt] above cash: at first order a bet on realized against implied, with vega, discrete hedging, surface dynamics and costs as the caveats.
  • Weighted by 1/K21/K^2, a strip of hedged options has a flat ΓS2\Gamma S^2 and replicates a variance swap, the construction behind the VIX.

10 · Check yourself

Question 1

Why must a random walk's step shrink like Δt\sqrt{\Delta t}, rather than like Δt\Delta t, for the walk to become Brownian motion?

Answer

A year of n=1/Δtn = 1/\Delta t independent steps of size hh has variance nh2=h2/Δtn h^2 = h^2/\Delta t. For that to stay at σ2\sigma^2 as the steps shrink, h2h^2 must equal σ2Δt\sigma^2\Delta t, so h=σΔth = \sigma\sqrt{\Delta t}. With h=σΔth = \sigma\Delta t instead, the variance is σ2Δt\sigma^2\Delta t, which vanishes, leaving a straight line.

Question 2

Apply Itô's lemma to V=S2V = S^2, and find dVdV.

Answer

Here ∂V/∂S=2S\partial V/\partial S = 2S, ∂2V/∂S2=2\partial^2V/\partial S^2 = 2 and ∂V/∂t=0\partial V/\partial t = 0. By (7A.5), dV=2S dS+σ2S2 dtdV = 2S\,dS + \sigma^2S^2\,dt, so that substituting (7A.2) gives dV=(2μ+σ2)S2 dt+2σS2 dWdV = (2\mu + \sigma^2)S^2\,dt + 2\sigma S^2\,dW. The ordinary chain rule would miss the σ2S2 dt\sigma^2S^2\,dt, which is why the square of the price drifts up faster than 2μ2\mu.

Question 3

Use (7A.13) to recover the reference call's theta from its other Greeks.

Answer

Rearranged, the equation gives Θ=rV−rSΔ−12σ2S2Γ=0.1208−2.1302−17.3363=−19.3457\Theta = rV - rS\Delta - \tfrac12\sigma^2S^2\Gamma = 0.1208 - 2.1302 - 17.3363 = -19.3457 a year. Divided by 365, that is a loss of about 5.3 cents a share a day, as Chapter 5C found by repricing.

Question 4

A dealer is short the at-the-money option of the worked example, with 12ΓS2=202\tfrac12\Gamma S^2 = 202 and implied volatility 20%. What does the day cost per contract if spot moves 2.52% today, twice the breakeven?

Answer

The bracket in (7A.15) is 0.02522−0.04/252=0.000635−0.000159=0.0004760.0252^2 - 0.04/252 = 0.000635 - 0.000159 = 0.000476. For the long option that is a gain of 202×0.000476=0.096202 \times 0.000476 = 0.096 a share, so the short dealer loses about $9.62 a contract. That is three times the $3.21 of implied variance the short collects on a quiet day.

Question 5

In the one-step tree, suppose the underlying ends at 120 or 90, with the strike at 100 and r=0r = 0. Price the call and find the risk-neutral probability of the rise.

Answer

The replica needs 120a+b=20120a + b = 20 and 90a+b=090a + b = 0, so a=2/3a = 2/3, b=−60b = -60 and the replica costs 66.67−60=6.6766.67 - 60 = 6.67. The risk-neutral probability pp makes the expected price 100: 120p+90(1−p)=100120p + 90(1 - p) = 100, so p=1/3p = 1/3. The expected payoff at that probability is 20/3=6.6720/3 = 6.67, the price.

Question 6

Why does a strip weighted by 1/K21/K^2 replicate a variance swap, while a single at-the-money option does not?

Answer

By (7A.15), each instant's gain is weighted by 12ΓS2\tfrac12\Gamma S^2. A single option's ΓS2\Gamma S^2 is large near its strike and tiny far from it, so its P&L depends on where spot happened to be when the big moves came. The 1/K21/K^2 strip has the same ΓS2\Gamma S^2 at every spot, so every squared return counts equally. The total is then a fixed multiple of realized less implied variance.