Part VI · Dealers · Chapter 6B

What the dealer inherits

The Greeks of a customer's trade

Where we are

Chapter 6A left the dealer short the call it sold you. This chapter lists what that short call carries, Greek by Greek, and takes apart the formula for the one the dealer hedges first: delta. It ends on the asymmetry the rest of this part works out, that delta is cheap to hedge and gamma is not.

What you need first
  • The five Greeks, and the Black-Scholes formula with d1d_1, d2d_2, NN and φ\varphi (Chapter 5C).
  • Delta as a hedge ratio rather than a probability (Chapter 5C).
  • Log returns and the natural logarithm (Chapter 1A), and the normal curve and z-scores (Chapter 1B).
  • Long and short positions (Chapter 4A), and the contract multiplier of 100 (Chapter 5A).

1 · A bundle of sensitivities

When the dealer sold you the call, it inherited a bundle of sensitivities. The option's value changes when the price of the underlying moves, when implied volatility (IV) moves, when time passes and when interest rates change. Each of these sensitivities is a Greek (Chapter 5C), and each must eventually be managed.

The inheritance is a sign flip: the dealer holds the other side of your contract, so each of its Greeks is the negative of yours.

GreekYour long callThe dealer's short callWhat it means for the dealer
DeltaPositiveShort deltaLoses if the underlying rises. Hedged in Chapter 6C.
GammaPositiveShort gammaIts delta moves against it. The subject of Chapter 6D.
ThetaNegativeLong thetaCollects as time passes: the compensation for accepting negative gamma.
VegaPositiveShort vegaLoses if IV rises, since the option becomes more valuable to you.
RhoPositiveShort rhoUsually negligible for short-dated options.

Vega is more expensive to hedge dynamically than delta. Most dealers manage vega in aggregate across their book rather than hedging each position.

2 · Delta, the Greek hedged first

Delta, the most important of them, is the partial derivative of the option's value with respect to the price of the underlying. If the underlying rises by $1, the option's value rises by about delta dollars. A call's delta lies between 0 and 1, and a put's between −1 and 0. Deep in-the-money (ITM) options behave almost like the underlying itself, with delta near ±1. Deep out-of-the-money (OTM) options barely react, with delta near 0, and at-the-money (ATM) options sit near ±0.5.

The Black-Scholes delta of a call uses the symbols of Chapter 5C: SS for the price of the underlying, KK for the strike and TT for the time to expiry in years. Implied volatility is σ\sigma, the risk-free rate rr and the dividend yield qq. In that notation, the call's delta is

Δcall=e−qT N(d1) \Delta_{\text{call}} = e^{-qT}\, N(d_1) (6B.1)
d1=ln⁡(S/K)+(r−q+12σ2) TσT d_1 = \frac{\ln(S/K) + (r - q + \tfrac12\sigma^2)\,T}{\sigma\sqrt{T}} (6B.2)

The same d1d_1 appears in every Greek of Chapter 5C, so it pays to read it piece by piece.

Reading d1d_1 piece by piece

  • The function N(⋅)N(\cdot) is the distribution function of the standard normal distribution. It takes any number on the real line and returns a probability between 0 and 1: the area under the bell curve to the left of that number.
  • The log term ln⁡(S/K)\ln(S/K) is the log-moneyness, the log return that would carry the strike to the spot (Chapter 1A). It is positive when spot is above the strike, which is in the money for a call, negative when spot is below, and zero exactly at the money.
  • The term (r−q+12σ2) T(r - q + \tfrac12\sigma^2)\,T adjusts for three things, beginning with the risk-free rate, which raises the forward price above spot, and the dividend yield, which lowers it. The term 12σ2\tfrac12\sigma^2 is the convexity correction: it accounts for the mean of the lognormal distribution sitting above its median in log space.
  • The denominator σT\sigma\sqrt{T} is the standard deviation of log returns over the TT years left. Dividing by it puts the log-moneyness on a common scale.

So d1d_1 is a z-score: it says, in standard deviations, how strongly the option is placed to finish in the money. Feeding it to NN gives a probability-like number. Multiplying by e−qTe^{-qT} adjusts for the dividends you forgo by holding the option rather than the stock itself.

Worked example: Delta of a call $5 in the money

Take S=105S = 105, K=100K = 100, 30 days to expiry (T=30/365=0.0822T = 30/365 = 0.0822), σ=20%\sigma = 20\%, r=4%r = 4\% and no dividend.

Step 1: the three pieces. The log-moneyness is ln⁡(105/100)=ln⁡1.05=0.0488\ln(105/100) = \ln 1.05 = 0.0488, and the drift term is (0.04+12×0.04)×0.0822=0.0049(0.04 + \tfrac12 \times 0.04) \times 0.0822 = 0.0049. The scale is σT=0.20×0.2867=0.0573\sigma\sqrt{T} = 0.20 \times 0.2867 = 0.0573.

Step 2: delta. By (6B.2), d1=(0.0488+0.0049)/0.0573=0.937d_1 = (0.0488 + 0.0049)/0.0573 = 0.937, and a table gives N(0.937)=0.826N(0.937) = 0.826. With no dividend e−qT=1e^{-qT} = 1, so the call's delta is 0.826.

Step 3: the dealer's exposure. A dealer short 10 of these calls is short 10×100×0.826=82610 \times 100 \times 0.826 = 826 share-equivalents, and its hedge is 826 shares.

3 · A hedge ratio, and only roughly a probability

Delta, the result of all this, is the dividend-discounted hedge ratio: the number of shares per contract, divided by the multiplier of 100, that neutralizes the option's first-order exposure to spot. The Black-Scholes call price, with d2=d1−σTd_2 = d_1 - \sigma\sqrt{T}, is

C=Se−qTN(d1)−Ke−rTN(d2) C = S e^{-qT} N(d_1) - K e^{-rT} N(d_2) (6B.3)

Its two NN terms are different probabilities under different weightings of the outcomes. N(d2)N(d_2) is the standard risk-neutral probability of finishing in the money. The call's delta, e−qTN(d1)e^{-qT}N(d_1), is the share-equivalent hedge ratio under the share-numeraire weighting of Chapter 5C. It is close to the chance of finishing in the money but not equal to it, and the gap grows as σT\sigma\sqrt{T} grows.

A 0.30-delta call behaves as 30 shares of the underlying per 100-share contract. That is its operative meaning, and it is what dealer hedging is built on. A share-equivalent is this unit of exposure: one share's worth of sensitivity to small moves in the underlying.

The informal reading, "a 30% chance of finishing in the money", is roughly right for short-dated options near the money and technically wrong. The chance of finishing in the money is N(d2)N(d_2), smaller than N(d1)N(d_1) by about φ(d1) σT\varphi(d_1)\,\sigma\sqrt{T}, where φ\varphi is the height of the standard normal curve (Chapter 5C).

Worked example: How far delta is from the probability

Step 1: a 30-day call. A 30-delta call with no dividend has N(d1)=0.30N(d_1) = 0.30, so d1=−0.524d_1 = -0.524. At 20% IV and 30 days, σT=0.0573\sigma\sqrt{T} = 0.0573, so d2=−0.582d_2 = -0.582 and N(d2)=0.280N(d_2) = 0.280, about 2 percentage points below the delta.

Step 2: a 90-day call at high volatility. At 60% IV and 90 days, σT=0.60×0.4966=0.298\sigma\sqrt{T} = 0.60 \times 0.4966 = 0.298. Then d2=−0.524−0.298=−0.822d_2 = -0.524 - 0.298 = -0.822 and N(d2)=0.205N(d_2) = 0.205, a gap of 9.5 points.

Step 3: the matching put. A 30-delta put there has d1=+0.524d_1 = +0.524 and d2=0.226d_2 = 0.226, so its chance of finishing in the money is 1−N(0.226)=0.4111 - N(0.226) = 0.411, 11 points above its delta.

When you hear a trader say they are "selling 25-delta puts", read it as a hedge ratio of 25 share-equivalents per contract, not as a 25% probability of assignment. For dealer mechanics the share-equivalent reading is the operative one. A dealer short 1,000 contracts of a 0.30-delta call is short 1,000×100×0.30=30,0001{,}000 \times 100 \times 0.30 = 30{,}000 share-equivalents. It behaves as if it were short 30,000 shares of the underlying, and it neutralizes that by buying 30,000 shares, as Chapter 6C describes.

4 · The geometry of d1d_1

Because d1d_1 is a z-score, delta has a picture. The area under the standard normal density to the left of d1d_1 is N(d1)N(d_1), which is the call's delta up to the dividend factor.

The figure below draws that density with d1d_1 marked on it, at a 4% rate and no dividend. Its sliders set spot and strike (each from 70 to 130), days to expiry (1 to 180) and implied volatility (5% to 80%). A button switches between a call and a put. The readouts give the three pieces of (6B.2): ln⁡(S/K)\ln(S/K), the drift term (r−q+12σ2)T(r - q + \tfrac12\sigma^2)T and d1d_1 itself, with N(d1)N(d_1) as the call's delta. It opens at the money, with spot and strike at 100, 30 days and 20% IV, where the readouts show 0.000, 0.0049, d1=0.086d_1 = 0.086 and a delta of 0.534. Set spot to 105 to reproduce the worked example, then switch to the put.

$100.0
$100
30d
20%
ln(S/K) = 0.000
(r−q+½σ²)·T = 0.0049
d₁ = 0.086
N(d₁) = call Δ = 0.534
d₁ is a z-score, and delta is an area. The standard normal density with d₁ = [ln(S/K) + (r − q + ½σ²)T] / (σ√T) marked on it, for the option the sliders set (r = 4%, q = 0). For a call the shaded area left of d₁ is N(d₁), the call's delta; for a put the area to the right is 1 − N(d₁), the size of the put's delta. Move spot through the strike and d₁ slides across the curve, carrying the delta with it.

At spot 105 the readouts match the worked example: d1=0.937d_1 = 0.937 and a call delta of 0.826. For the put the shaded area moves to the right of d1d_1, and 1−N(d1)=0.1741 - N(d_1) = 0.174 is the size of the put's delta. Now keep spot at 105 and drag the days to expiry. At 1 day d1d_1 reaches 4.68, past the chart's right edge, where its marker stops, and delta reaches 1.000: the call is almost certain to finish in the money. At 180 days d1d_1 falls to 0.558 and delta to 0.712. Raising IV to 80% at 30 days has a similar effect, pulling d1d_1 back to 0.342 and delta to 0.634. More uncertainty makes the in-the-money finish less certain, so delta moves toward the middle.

5 · Why an at-the-money call has a delta above one half

With spot equal to the strike the log-moneyness is zero, and (6B.2) becomes

d1=(r−q)Tσ+12 σT d_1 = \frac{(r - q)\sqrt{T}}{\sigma} + \tfrac12\,\sigma\sqrt{T} (6B.4)

The second term is always positive, and the first is not negative when r≥qr \ge q, so an at-the-money call then has N(d1)N(d_1) above 0.5. The second term, from the convexity correction 12σ2\tfrac12\sigma^2, grows with volatility and time. It is what makes high-volatility options drift higher in delta even at the money.

Worked example: The drift of at-the-money delta

Step 1: the figure's reading. At the money with 30 days, the figure gives a delta of 0.534 at 20% IV. Raising IV to 80% lifts it to 0.551, and 180 days at 80% lifts it to 0.624.

Step 2: the convexity part alone. With r=q=0r = q = 0, (6B.4) leaves d1=12×0.80×180/365=0.281d_1 = \tfrac12 \times 0.80 \times \sqrt{180/365} = 0.281, and N(0.281)=0.611N(0.281) = 0.611. So of the 0.124 by which the 180-day delta exceeds one half, 0.111 comes from the convexity correction and only 0.013 from the 4% rate.

The reason is the shape of the lognormal distribution. Suppose a stock at 100 ends a period with a log return of either +0.2 or −0.2, with equal chance. It ends at 100e0.2=122.14100e^{0.2} = 122.14 or at 100e−0.2=81.87100e^{-0.2} = 81.87: a gain of $22.14 against a loss of $18.13. The two log returns average zero, which puts the middle of the distribution, in log terms, at a price of 100. The average price, though, is (122.14+81.87)/2=102.01(122.14 + 81.87)/2 = 102.01. Even with no expected move in log terms, high volatility means more upside than downside in dollars, because the lognormal distribution is right-skewed by construction.

Familiar ground

You have seen this shape in survival data. Survival times are right-skewed: a few long survivors pull the mean above the median, which is why trials report the median. A price whose log is normal has the same shape, with its mean above its median, and the gap between them widens as the spread grows. The 12σ2T\tfrac12\sigma^2 T in the numerator of d1d_1 is the size of that gap on the log scale.

6 · The asymmetry that drives the rest of this part

The dealer can hedge delta easily and cheaply, by buying or selling shares of the underlying. It cannot hedge gamma cheaply, except by acquiring offsetting options positions. So most dealer books are not gamma-hedged in the literal sense. They carry net gamma exposure and manage it through dynamic delta re-hedging, which is the setup for Chapter 6D onward.

Key idea

Shares can neutralize delta and nothing else, while gamma, vega and the rest can be offset only with other options. So a dealer carries its gamma and keeps re-hedging the delta that gamma moves.

In practice
  • Count every option position in share-equivalents: contracts × 100 × delta. A position of 10 long 0.30-delta calls behaves, for small moves, like 300 shares.
  • Know what the dealer holds against you. It holds the negative of each of your Greeks, so its re-hedging is driven by the gamma you bought.
  • Use N(d2)N(d_2) for the odds of assignment, not delta, and 1−N(d2)1 - N(d_2) for a put. A short 25-delta put has a risk-neutral chance of finishing in the money above 25%, and further above it at high IV or long expiries.
When it fails

A delta is one model's number at one implied volatility, so a hedge computed at the wrong IV is the wrong hedge. Delta also drifts with spot, with time and with IV (Chapter 5D), so a share-equivalent count is right only now and only for small moves. The rest of this part is about what that drift forces the dealer to do.

Common mistake: "30-delta means a 30% chance"

Delta reads the normal curve at d1d_1, while the chance of finishing in the money reads it at d2d_2, σT\sigma\sqrt{T} lower. For a 30-day, 30-delta call at 20% IV the two differ by about 2 points, and for a 90-day put at 60% IV by 11. Read delta as shares, and compute the probability separately when you need it.

Decision rule
  • Before holding an option position, write down its size in share-equivalents. If that exceeds the share position you would be willing to hold outright, reduce the number of contracts.
  • Estimate assignment odds from N(d2)N(d_2), and treat even that as a risk-neutral figure, not a forecast (Chapter 5C).
What to carry forward
  • Selling you an option hands the dealer the negative of each of your Greeks: short delta, short gamma, long theta, short vega and short rho.
  • Call delta is e−qTN(d1)e^{-qT}N(d_1), where d1d_1 is a z-score for how strongly the option is placed to finish in the money.
  • Delta is a hedge ratio in share-equivalents, while the chance of finishing in the money is N(d2)N(d_2), with a gap that grows with σT\sigma\sqrt{T}.
  • The convexity correction 12σ2\tfrac12\sigma^2 lifts an at-the-money call's delta above one half, more so at high volatility and long expiries.
  • Shares hedge delta cheaply, but only options hedge gamma, so dealers carry gamma and re-hedge delta.

7 · Check yourself

Question 1

A dealer is short 50 contracts of a call with a delta of 0.62. What is its exposure, and what is its hedge?

Answer

It is short 50×100×0.62=3,10050 \times 100 \times 0.62 = 3{,}100 share-equivalents, so it buys 3,100 shares.

Question 2

What are d1d_1 and the call's delta for an option with spot equal to strike, r=q=0r = q = 0, σ=20%\sigma = 20\% and three months to expiry?

Answer

By (6B.4), d1=12×0.20×0.25=0.05d_1 = \tfrac12 \times 0.20 \times \sqrt{0.25} = 0.05, which gives a delta of N(0.05)=0.520N(0.05) = 0.520. It is above one half with no help from rates, because of the convexity correction.

Question 3

Which of the dealer's inherited Greeks can it neutralize by trading the underlying alone?

Answer

Only delta, because shares have a delta of 1 and no gamma, theta or vega, so offsetting gamma or vega needs other options.

Question 4

In the figure, the call at spot 105 has a delta of 0.826 with 30 days left at 20% IV. Which way does delta move if IV rises to 80%, and why?

Answer

It falls to 0.634. The larger σT\sigma\sqrt{T} divides the log-moneyness by a bigger number and pulls d1d_1 from 0.937 to 0.342: more uncertainty makes the in-the-money finish less certain.